Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Can someon please explained to me how we are supposd to figure out the son\'s ba

ID: 174385 • Letter: C

Question

Can someon please explained to me how we are supposd to figure out the son's banding pattern when he has Klinefelter’s (XXY) male progeny based off the parent's potential non-disjunction for each scenerio (A, B & C). I'm jus really confused on how to approach it.

1. Below are shown pedigrees from 3 families (abeled A, B and C), all of which has a digested with a restriction enzyme, run on a gel and then probed with a labeled X linked piece of DNA that identifies two distinct RFLP morphs. The gel patterns for the parents are shown below, however the banding pattern for the Klinefelter's son is not shown. For each pedigree draw the son's banding pattern that would lead you to conclude that: Family A had a non-disjunction event in meiosis 2 of the mother (there are no other possibilities) Family B had a non-disjunction event in meiosis 1 of the father or meiosis 1 of the mother (there are the only two possibilities). Family Chad a non-disjunction event in meiosis 1 of the father (there are no other possibilities)

Explanation / Answer

A.)

In the case of Klinefelter’s syndrome male progeny has XXY condition; it means he has one extra X chromosome. Due to which he has many phenotypic conditions, however in this case to understand this condition one can should check for the extra chromosome bands in the gel.

All of the progeny will have two bands, father has one band and mother has two bands.

In case of family A: Non disjunction at meiosis-II caused in mother will cause to form 2 gametes with X-chromosome each normal and one gametse with extra set of x chromosomes (n + 1) leaving other gametes empty.

In case of family B: Non disjunction at meiosis-I leads to production of two gametes without X-chromosomes and two gametes with extra set of X-chromosomes (n + 1).

In case of Family C: here father has non disjunction at meiosis-I, which leads to production of one gametes without X-chromosomes and one gametes with extra set of X-chromosomes (n + 1).