A pendulum is observed to make 20 round trip swings in 25seconds.?

Question

a. What is the frequency of this pendulum? 0.8Hz
b. What is the period of this pendulum? 1.25s
c. What is the period of this pendulum in min?
d. What is the length of this pendulum?
I just didnt know how to do c and d. Can someone show me the steps?THanks!! a. What is the frequency of this pendulum? 0.8Hz
b. What is the period of this pendulum? 1.25s
c. What is the period of this pendulum in min?
d. What is the length of this pendulum?
I just didnt know how to do c and d. Can someone show me the steps?THanks!!

Explanation / Answer

(a). time taken for 20 round s = 25 s So, time taken for 1 round T = 25 s / 20 = 1.25s i.e., period of time T = 1.25 s So, frequency of the pendulum f = 1/ T                                                  = 0.8 Hz (b). period of thependulum T = 1.25 s (c).   T = 1.25 s            =( 1.25 / 60 ) min            =0.0208 min (d). we know T = 2 [ L / g ] from this length of the pendulum L = g T2 / ( 4 2 ) where g = 9.8 m / s ^ 2            T = 1.25 s substitue values we get answer

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