Please help with this problem! I don't understand how to do itand I need it very urgently. So i would appreciate if you couldjust show the steps and then the answer so I can check my work.Thanks so much! A locust jumps by extending its hind legs against the ground.Experiments indicate that a 3.0 g locust exerts an average force ofabout .45 N against the floor, at angle of 57.During the acceleration period the locust's body moves a distanceof 4.0 cm. (draw force body diagram and use sum of forces notation) calculate: a. The net force acting on the locust b. the locust's acceleration c. It's take off velocity d. the distance you might expect the locust to travel duringthe jump if we ignore air resistance.
Explanation / Answer
Fy = F sin - m g = .45 sin 57 - .003 * 9.8 =.348 N Fx = F cos = .45 cos 57 = .245 N FT = (.3482 + .2452) =.426 N net force a = F / m = .426 / .003 = 142 m /s2 acceleration 2 a s = v2 = 2 * 142 *.04 v = 3.37 m /s the take-off speed h = vy t - 1/2 g t2 =0 where t is the total time in the air andh the net height vy = v sin = 3.37 * sin 57 = 2.83 m /s t = 2 vy / g = = .578 sec x = vx t wherevx is the horizontal speed at which the locustleaves the ground x = v cos * t = 3.37 * cos 57 * .578 = 1.06m