Need help with a practice test, please explain step by step, I hadto miss the cl

Question

Need help with a practice test, please explain step by step, I hadto miss the class where he explained this so I'm not sure whatsgoing on...


The wheel of a grindstone has a constant angular acceleration of0.35 rad/s2. It starts from rest with an arbitraryreference line.
a) What is the angular displacement of the reference line (andhence of the wheel) during the interval from t=0s to t=18s? (Giveanswer in degrees)
b) What is the angular speed of the wheel at t=18s? Provide youranswer in rpm.


Thanks a lot, any help is appreciated

Explanation / Answer

Given :           Angularacceleration      = 0.35 rad/ s2 (a)     We know that   = / t Angular velocity is :    = * t    = 0.35 *( 18 - 0)                                                             = 6.3 rad /s (b)         Angular speed is:   = (t) = 0.35 * 18   = 6.3 rad/s                                                                                      = 6.3 * 60 rad /m                                                                                   = 378 rpm Hope this helps u!                                                                                                   (a)     We know that   = / t Angular velocity is :    = * t    = 0.35 *( 18 - 0)                                                             = 6.3 rad /s (b)         Angular speed is:   = (t) = 0.35 * 18   = 6.3 rad/s                                                                                      = 6.3 * 60 rad /m                                                                                   = 378 rpm Hope this helps u!                                                                                                  

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