(b1) What is the ratioKE after /KE before of the total kineticenergy after the c

Question

(b1) What is the ratioKEafter/KEbefore of the total kineticenergy after the collisions occur to that before the collisionsoccur?

Part A) A bullet that has a massof mbullet = 3.60g is moving horizontally with a velocityof = +348 m/s, where the + sign indicatesthat it is moving to the right (see thepart a of the drawing). The mass of the firstblock is mblock 1 = 1130g, and its velocity is = +0.550 m/s after the bullet passesthrough it (see part b of the drawing). The massof the second block is mblock2 = 1560 g.

(a1) What is the velocity of the second block after the bullet imbeds itself?Include a plus or minus sign in your answer to denotedirection.

Explanation / Answer

Applying the law of conservation of momentum we have the speedof bullet after passing the block1 is m1u1+m2u2=m1v1+m2v2 3.6*10-3*348+1.13*0=3.6*10-3*v+1.13*0.55 v=175.361m/s For the block2 we have as, 3.6*10-3*175.361+1.56*0=(3.6*10-3+1.56)v v=0.4037478m/s Hence we get by it.

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