Suppose between the cathode and anode vof an x-ray tube thereexists an electric field of 25,0000.0 NC^-1. What is the acceleration of an electron in this field? ans: is this eq. correct - E=F/qe=f=qe x E(I am also havingproblems writing these symbols) Thanks to anyone who can help me with this problem. Suppose between the cathode and anode vof an x-ray tube thereexists an electric field of 25,0000.0 NC^-1. What is the acceleration of an electron in this field? ans: is this eq. correct - E=F/qe=f=qe x E(I am also havingproblems writing these symbols) Thanks to anyone who can help me with this problem.
Explanation / Answer
F=eq=1.6*10-19*2.5*105=4*10-14N F=ma a=4*10-14/9.1*10-31 a=4.3956*1016m/s2 Hence we get by it. a=4.3956*1016m/s2 Hence we get by it.