The moment of inertia of a solid cylinder about its axis isgiven by 0.5MR2. If t

Question

The moment of inertia of a solid cylinder about its axis isgiven by 0.5MR2. If this cylinder rolls without slipping, the ratioof its rotational kinetic energy to its translational kineticenergy is what? Please give step by step instructions with solution fot 10points The moment of inertia of a solid cylinder about its axis isgiven by 0.5MR2. If this cylinder rolls without slipping, the ratioof its rotational kinetic energy to its translational kineticenergy is what? Please give step by step instructions with solution fot 10points

Explanation / Answer

I = 0.5MR2, its rotational kinetic energy = RK = 0.5I2 =0.5*(0.5MR2)2 its translational kinetic energy = TK = 0.5Mv2 =0.5M(R)2 so the ratio RK/TK = 0.5

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