Doubly ionized lithium Li 2+ ( Z = 3) and triply ionized beryllium Be 3+ ( Z = 4

Question

Doubly ionized lithium Li2+(Z = 3) and triply ionized beryllium Be3+(Z = 4) each emit a line spectrum. For a certain series oflines in the lithium spectrum, the shortest wavelength is253.5 nm. For the same series of lines inthe beryllium spectrum, what is the shortest wavelength?
1 nm

PLEASE SOLVE WITH NUMBER . I REALLY NEEDTHAT ANSWER TO SUBMIT THE HW PLEASE HELP ME. THANK YOU Doubly ionized lithium Li2+(Z = 3) and triply ionized beryllium Be3+(Z = 4) each emit a line spectrum. For a certain series oflines in the lithium spectrum, the shortest wavelength is253.5 nm. For the same series of lines inthe beryllium spectrum, what is the shortest wavelength?
1 nm

PLEASE SOLVE WITH NUMBER . I REALLY NEEDTHAT ANSWER TO SUBMIT THE HW PLEASE HELP ME. THANK YOU

Explanation / Answer

   the shortest wavelength is given by    Be = (Z2)Li / Z2Be           =....... nm           =....... nm

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