1) Under normal conditions, you are just barely able to lift a massof 92 kg. You

Question

1) Under normal conditions, you are just barely able to lift a massof 92 kg. Your friend drops a box ofvolume 2.9m3 into a lake. If you are just able to lift itto the surface, what is the mass of the box?
1 kg

2) An object has a weight of 15 N inair and an apparent weight of 5.4 Nwhen submerged in water. What is its density?
1 kg/m3

3) You want to design a helium-filled balloon that will lift atotal payload of 1445 kg. What volumeof helium is needed to just barely lift this payload?
1 m3 2.9m3 into a lake. If you are just able to lift itto the surface, what is the mass of the box?
1 kg

2) An object has a weight of 15 N inair and an apparent weight of 5.4 Nwhen submerged in water. What is its density?
1 kg/m3

3) You want to design a helium-filled balloon that will lift atotal payload of 1445 kg. What volumeof helium is needed to just barely lift this payload?
1 m3

Explanation / Answer

1)mass able to lift m = 92 kg volume of box V = 2.9 m^3 let mass of the box be m the buoyant force is B = fluid * g * V or m * g = fluid * g * V or m = fluid * V fluid= 1000 kg/m^3 substitute the values 2)buoyant force on the object is B = Fg - T2 Fg= 15 N and T2= 5.4 N buoyant force is equal in magnitude of the displacedwater, wgVw= B Here,Vo= Vw=(B/wg) the density of the object is o= (mo/Vo) or o= (mo/(B/wg))= (mo* wg/B) mo= (Fg/g) or o= ((Fg/g) *wg/B) = (Fg*w/B) substitute the values 3)the bouyant force on the balloon should be zerotherefore B = Fg - T2 = 0 or Fg = T2 or m * g = m2 * g = * V * g or V = (m/) m = 1445 kg and (density of helium gas) = 0.00018 g/mL= 0.00018 * (10^-3/10^-3 * 10^-3) kg/m^3 = 0.18 kg/m^3 substitute the values or m * g = m2 * g = * V * g or V = (m/) m = 1445 kg and (density of helium gas) = 0.00018 g/mL= 0.00018 * (10^-3/10^-3 * 10^-3) kg/m^3 = 0.18 kg/m^3 substitute the values

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