Two boxes, A and B, are connected by a (mass-less) cord andare resting on a smooth (frictionless) table. The boxes have massesof 12.0 kg and 10.0 kg. A horizontal force (Fp) of 40.0N is applied to the 10.0kg box. (a.) Find the acceleration of each box. (b.) Find the tension force in the cord connecting the twoboxes. Two boxes, A and B, are connected by a (mass-less) cord andare resting on a smooth (frictionless) table. The boxes have massesof 12.0 kg and 10.0 kg. A horizontal force (Fp) of 40.0N is applied to the 10.0kg box. (a.) Find the acceleration of each box. (b.) Find the tension force in the cord connecting the twoboxes.
Explanation / Answer
the system is accelerated by the force Fp. N2 Law: F=ma a=F/(m1+m2)=40N/(10kg+12kg)=1.818m/s2 part b: Force need to accelerate the secondmass=m2*a=12*1.818=21.816N therefore the tension is 21.816N part b: Force need to accelerate the secondmass=m2*a=12*1.818=21.816N therefore the tension is 21.816N