A sports car is accelerating up a hill that rises 15.0° above the horizontal. Th

Question

A sports car is accelerating up a hill that rises 15.0° above the horizontal. The coefficient ofstatic friction between the wheels and the road isµs = 0.79. It isthe static frictional force that propels the car forward. (a) What is the magnitude of the maximumacceleration that the car can have?
1 m/s2

(b) What is the magnitude of the maximum acceleration if the car isbeing driven down the hill?
2 m/s2 (a) What is the magnitude of the maximumacceleration that the car can have?
1 m/s2

(b) What is the magnitude of the maximum acceleration if the car isbeing driven down the hill?
2 m/s2

Explanation / Answer

(a). maximum accleration a = g sin + g cos where = The coefficient of static frictionbetween the wheels and the road = 0.79           = angle = 15 degrees So, a = 10.01 m / s ^ 2 (b). maximum accleration a = g sin - g cos                                            =-4.941 m / s ^ 2           = angle = 15 degrees So, a = 10.01 m / s ^ 2 (b). maximum accleration a = g sin - g cos                                            =-4.941 m / s ^ 2

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