Under constant pressure, the temperature of 2.40 mol of an ideal monatomic gas i

Question

Under constant pressure, the temperature of 2.40 mol of an ideal monatomic gas is raised12.0 K. (a) What is the work W done by thegas?
1 J

(b) What is the energy transferred as heat Q?
2 J

(c) What is the change Eint in theinternal energy of the gas?
3 J

(d) What is the change K in the average kineticenergy per atom?
4 J (a) What is the work W done by thegas?
1 J

(b) What is the energy transferred as heat Q?
2 J

(c) What is the change Eint in theinternal energy of the gas?
3 J

(d) What is the change K in the average kineticenergy per atom?
4 J

Explanation / Answer

Given :   n = 2.40 mol              T = 12.0 K (a)       Workdone :   W = n R T   = 2.40 * 8.314 * 12                                                   = 239.44 J (b)      Q = n cpT           = 2.40 * (5/2) R * 12           = 2.40 * ( 5 /2) * 8.314 * 12           = 598.608 J (c)          Eint  = Q - W   = 598.608 - 239.44                                         = 359.168 J (d)       K   = 3/2 K T               = 3 /2 * 1.38 x 10-23* 12               = 2.484 x 10-22 J Hope this helps u!

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