A typical nuclear power plant converts 0.01% of themass of its fuel into energy

Question

A typical nuclear power plant converts 0.01% of themass of its fuel into energy through nuclear reactions. How muchfuel would be needed to power an average city for oneday? Express the mass of fuel needed in kilograms to twosignificant figures.
A typical nuclear power plant converts 0.01% of themass of its fuel into energy through nuclear reactions. How muchfuel would be needed to power an average city for oneday? Express the mass of fuel needed in kilograms to twosignificant figures.
Express the mass of fuel needed in kilograms to twosignificant figures.

Explanation / Answer

Average energy used E = 8.5 * 10 ^ 13 J energy per fission = 208 MeV                            = 208 * 1.6 * 10 ^ -13 J efficiency = 0.01 % energy coming out from one fission E ' = ( 0.01 / 100) * 208 * 1.6 * 10 ^ -13 J                                                           = 332.8 * 10 ^ -17 J So, No.of fissions to produce E energy N = E/ E '                                                                   = 25.54 * 10 ^ 23 Mass of 1 mole ( 6.023 * 10 ^ 23 ) = 235 g So, mass of N nucleons = 235 g * ( N / 6.023* 10 ^ 23 )                                        = 996.496 g                                        = 0.996496 kg                                        ~ 1 kg

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