About part d of question 55, how does the current not changewhen it went from .2
ID: 1749273 • Letter: A
Question
About part d of question 55, how does the current not changewhen it went from .21A to .25A? With the internal resistance, thecurrent through A is less than without the internal resistance. Sowhy is there no change in hte current through A? Is it just too insignifacnt? About part d of question 55, how does the current not changewhen it went from .21A to .25A? With the internal resistance, thecurrent through A is less than without the internal resistance. Sowhy is there no change in hte current through A? Is it just too insignifacnt?Explanation / Answer
(a) When the switch is open then the total resistance in thecircuit
6 + 0.5 = 6.5
Totalresistance = 3 +0 .5 =3.5
Current = 1.5/3.5
Out of this current and left shall flow through A & B each
c) Change in Current = 0.29 – 0.21 = 0 .08 A
Fractional change 0.08/0.29
(d) If the internal resistance of the battery be zero then when theswitch is open then current A = =1.5/6= .25A
When switch is closed, then total resistance is above = 3
Current = 1.5 / 3 =0 .5 A