A guitar string is 80 cm long andhas a mass of 3.6 g. The distance from the brid

Question

A guitar string is 80 cm long andhas a mass of 3.6 g. The distance from the bridge to the supportpost is L = 60 cm, and the string is under a tension of501 N. What is the frequency of thefundamental?
Hz
What is the frequency of the first overtone?
Hz
What is the frequency of the second overtone?
Hz A guitar string is 80 cm long andhas a mass of 3.6 g. The distance from the bridge to the supportpost is L = 60 cm, and the string is under a tension of501 N. What is the frequency of thefundamental?
Hz
What is the frequency of the first overtone?
Hz
What is the frequency of the second overtone?
Hz

Explanation / Answer

The fudamental frequency is given by             f = (1/(2l))((TL)/m) Here m = 3.6*10^-3 kg         T = 501 N        L = 0.80m         l = 0.60 m Substitute the values for f. The frequency of the first overtone is              f1 = 2f The frequency of the second overtone is           f2 =3f Substitute the values.

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