The difference in potential between a cathode and anode of aspark plug is 1.0 x 10^4 V. a. What energy does the electron give up as it passes betweenelectrodes? b. One-forth of the energy given up by the electron isconverted to electromagnetic radiation. The frequency of the waveis related to the energy by the equation E = hf, whereh is Planck's constant, 6.6 x 10^-34 J/Hz. What is thefrequency of the waves? The difference in potential between a cathode and anode of aspark plug is 1.0 x 10^4 V. a. What energy does the electron give up as it passes betweenelectrodes? b. One-forth of the energy given up by the electron isconverted to electromagnetic radiation. The frequency of the waveis related to the energy by the equation E = hf, whereh is Planck's constant, 6.6 x 10^-34 J/Hz. What is thefrequency of the waves?
Explanation / Answer
a) The energy of the electron is W = Vq Here V = 1.0 x 10^4 V and q =1.6*10-19C b) We know that E = hf Here E = W/4 h=6.626*10-34 Js So, the frequency of the wave is f = E/h Substitute the values.