The work done by an ideal gas in an isothermal expansion fromvolume V 1 to volum

Question

The work done by an ideal gas in an isothermal expansion fromvolume V1 to volume V2 isgiven by the formula:
W = nRTln(V2/V1)
Standard atmospheric pressure (1 atm) is 101.3 kPa. If 1.0 L of Hegas at room temperature (20ºC) and 1.0 atm of pressure iscompressed isothermally to a volume of 100 mL, how much work isdone on the gas? The work done by an ideal gas in an isothermal expansion fromvolume V1 to volume V2 isgiven by the formula:
W = nRTln(V2/V1)
Standard atmospheric pressure (1 atm) is 101.3 kPa. If 1.0 L of Hegas at room temperature (20ºC) and 1.0 atm of pressure iscompressed isothermally to a volume of 100 mL, how much work isdone on the gas? W = nRTln(V2/V1)

Explanation / Answer

the work done on the ideal gas W = n * R * T * ln(V2/V1) n = 1 mol R = 8.314 J/kg/K T = 20 oC = (20 + 273) K = 293 K V2 = 100 mL = 100 * 10^-3 L V1 = 1.0 L

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