Mike throws a ball upward & toward the east at a 63.0 m/s at the instant he rele
ID: 1751608 • Letter: M
Question
Mike throws a ball upward & toward the east at a 63.0 m/s at the instant he releases the ball. What is the ball's initial angle in Nancy's reference frame?m/s. Nancy drives east past Mike at30.0 degree angle with a speed of22.0Explanation / Answer
In earth frame, (with x-axis towards east and y-axis upwards), ball velocity = (vx , vy) = (22cos630, 22 sin630) >>> the 1stnumber is x-component, the 2nd is y-component nancy's velocity = (30, 0) In nancy's reference frame, the two velocities are ball velocity = ( 22 cos630 - 30, 22sin630) nancy's velocity = (30 - 30, 0) = (0,0) You can find the ball's initial angle in nancy's frame from theformula angle = tan-1 (vy/vx) =tan-1[(22 sin630 )/(22 cos630 -30)] >>> watch out for the correct quadrant. Hope this helps!