Please include ALL conceptual AND mathematic steps so I canunderstand. Thanks A

Question

Please include ALL conceptual AND mathematic steps so I canunderstand. Thanks
A simple single-lens camera (biconvex lens) is used tophotograph a man 1.79 m tall who is standing 4.8 m from the camera.If the man's image fills the length of a frame of film (36.3 mm),what is the focal length of the lens?
Please include ALL conceptual AND mathematic steps so I canunderstand. Thanks
A simple single-lens camera (biconvex lens) is used tophotograph a man 1.79 m tall who is standing 4.8 m from the camera.If the man's image fills the length of a frame of film (36.3 mm),what is the focal length of the lens?

Explanation / Answer

Let me try to post this one more time, though very late. Magnification, m' = I/O = 36.3 mm/1790 = 0.020279 Iage distance, v =m'.u = 0.020279x4.8 = 0.09734 m Lens forula using sign convention real +ve, virtual -ve;           1/v +1/u = 1/f         1/f = 1/0.09735 +1/4.8 = 10.4816 Focal length,            f = 1/10.4816 = 0.0954 m = 9.54 cm Sorry, because of internet access failure I couldnt post thisearlier. All the best.

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