Could someone please help me with this question. I\'m not soworried about gettin

Question

Could someone please help me with this question. I'm not soworried about getting the answer. I'm more concerned aboutseeing the steps and having them explained so I can understand whatis taking place. I'm taking this class in summer school andit is moving so fast. My teacher does not have time to breakthings down or show us how to do it. So I would be verygrateful if you could do that for me.
Thanks.

A disk rotates with constant angular acceleration. The initialangular speed of the disk is 2 rad/s. After the disk rotates through12 radians, the angular speedis 14 rad/s. (a) What is the magnitude of the angularacceleration?
1rad/s2

(b) How much time did it take for the disk to rotate through12 radians?
2 s

(c) What is the tangential acceleration of a point located at adistance of 7.6 cm from the center of thedisk?
3m/s2

(a) What is the magnitude of the angularacceleration?
1rad/s2

(b) How much time did it take for the disk to rotate through12 radians?
2 s

(c) What is the tangential acceleration of a point located at adistance of 7.6 cm from the center of thedisk?
3m/s2

Explanation / Answer

Angular and translational motions are similar. The governingequations are (t)=o + (t) t +0.5t2 (t)= o + t since we know that o=2 rad/s and(t)= 14 rad/s when (t)=12 radians we canwrite (t)=o + (t) t +0.5t2 (t)= o + t as (t)=o + (t) t +0.5t2 (t)= o + t 12 = 0 + 14 t +0.5t2 14 = 2 + t ; then=12/t   substituting in the firstequation 12 = 0 + 14 t +0.5(12/t)t2 12 = 14 t + 0.5(12)t 12 = 20 t t= 12/20 t=0.6 s then since =12/t = 12/0.6 = 20 rad/s2 That provides the answer for a and b c) aT= R aT= 20 x 0.076 aT= 4.78m/s2   Please let me know if you have any further questions. Please let me know if you have any further questions.

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