In the Figure, a 0.23 kg block of cheese lies on the floor of a880 kg elevator c

Question

In the Figure, a 0.23 kg block of cheese lies on the floor of a880 kg elevator cab that is being pulled upward by a cable throughdistance d = 2.2 m. If the normal force onthe block from the floor has constant magnitudeFN = 3.2 N, how much work is doneon the cab by the force from the cable?

In the Figure, a 0.23 kg block of cheese lies on the floor of a880 kg elevator cab that is being pulled upward by a cable throughdistance d = 2.2 m . If the normal force onthe block from the floor has constant magnitude FN = 3.2 N , how much work is doneon the cab by the force from the cable?

Explanation / Answer

The normal force is just the force pushing up on thechesse. To find the force that is pulling up on the chesseyou need to find the force from gravity .23*9.8=2.254 N 3.2-2.254=.946 N You can use this to find the acceleration of theelevator. .946/.23=4.113 m/s^2 then you can use this to find the overall force exerted on theelevator. 4.113*880.23 kg=3620.424 N times that by the distance for work 3620.424*2.2=7962.93 J of work done.

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