A merry-go-round has a moment of inertia I, and a radius R. Aperson with mass m is standing at the centerof the merry-go-roundwhen it has an angular velocity w0. What will the angular velocitybe after the person walked away from the center halfway to therim? A merry-go-round has a moment of inertia I, and a radius R. Aperson with mass m is standing at the centerof the merry-go-roundwhen it has an angular velocity w0. What will the angular velocitybe after the person walked away from the center halfway to therim?
Explanation / Answer
according to the law of conservation of angular momentum wehave I * w = I1 * w1 or w1 = (I * w/I1) I = (M * R^2/2) and I1 = (m * r^2/4) or w1 = ((M * R^2/2) * w/(m * r^2/4)) here,r = (R/2) and w = wo or w1 = (M/m) * (R/(R/2))^2 * wo or w1 = (4M/m) * wo here,w1 is the angular velocity of the person after he walkedaway from the center halfway to the rim here,w1 is the angular velocity of the person after he walkedaway from the center halfway to the rim