Starting from rest, a disk rotates about itscentral axis with constant angular a

Question

Starting from rest, a disk rotates about itscentral axis with constant angular acceleration. In 6.0 s, it rotates 10rad. (a) What was the angular acceleration duringthis time?
rad/s2

(b) What was the average angular velocity?
rad/s

(c) What is the instantaneous angular velocity of the disk at theend of the 6.0 s?
rad/s

(d) Assuming that the acceleration does not change, through whatadditional angle will the disk turn during the next 10.0 s?
rad Starting from rest, a disk rotates about itscentral axis with constant angular acceleration. In 6.0 s, it rotates 10rad. (a) What was the angular acceleration duringthis time?
rad/s2

(b) What was the average angular velocity?
rad/s

(c) What is the instantaneous angular velocity of the disk at theend of the 6.0 s?
rad/s

(d) Assuming that the acceleration does not change, through whatadditional angle will the disk turn during the next 10.0 s?
rad (a) What was the angular acceleration duringthis time?
rad/s2

(b) What was the average angular velocity?
rad/s

(c) What is the instantaneous angular velocity of the disk at theend of the 6.0 s?
rad/s

(d) Assuming that the acceleration does not change, through whatadditional angle will the disk turn during the next 10.0 s?
rad

Explanation / Answer

(a)the angular displacement of the disk is = wot + (1/2)t^2 = 10 rad,wo= 0,t = 6.0 s and is theangular acceleration during this time or = [2( - wot/t^2]-------------(1) (b)the average angular velocity w^2 - wo^2 = 2 or w = [wo^2 + 2]^(1/2) the value of is obtained from equation (1) (c)the instantaneous angular velocity of the disk at the endof the 6.0 s w = wo + t ------------(2) (d)the additional angle through which the disk willturn during the next 10.0 s 1 = wt + (1/2)t^2 the value of w is obtained from equation (2) and t = 10.0s

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