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Mary\'s old prescription corrected her vision when her near pointwas at 60cm, bu

ID: 1754117 • Letter: M

Question

Mary's old prescription corrected her vision when her near pointwas at 60cm, but her eyesight is getting worse. Now she needs newglasses with a power of 2.67 Diopters. Assume n=2.
1. What's the power of her old glasses? 2. Where is her new near point located? 3. Is she getting more nearsighted/farsighted? EXPLAIN! 4. If you're trying to modify her old glasses to correct hervision, do you need to make the lenses flatter or more curved?EXPLAIN! 5. What is the fractional change (1 -rnew/rold) in the radius of curvature of thesymmetric thin lenses that will achieve the desired result?
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1. What's the power of her old glasses? 2. Where is her new near point located? 3. Is she getting more nearsighted/farsighted? EXPLAIN! 4. If you're trying to modify her old glasses to correct hervision, do you need to make the lenses flatter or more curved?EXPLAIN! 5. What is the fractional change (1 -rnew/rold) in the radius of curvature of thesymmetric thin lenses that will achieve the desired result?
Please show ALL work! I promise to rate you as lifesaver ifyour answer is correct!

Explanation / Answer

taking actual near point as object distance and changed nearest point of accomodation as imagedistance        1 /f = 1 /p + 1/ q       1 /f = 1/25.0cm + 1 / -60cm since the image is virtual taking negative for qvalue from the above relation we can solve for f     f = 43 cms positive values of f indicates , converging lense (1)power of old lense p = 1/ f (2) given the new focal length f ' = 100 /2.67 =37.5cm        and new nearest point 'q' ' can be determined as          1/ p + 1 /q'= 1 /f'      p = 25cms from the abv relation we can solve for q' >60cm (3) the curvature of the lense must be decreased so as todecrease the focal length,     she is getting more farsightedness , sincethe capabilitys to see near by obejects is increasing . 4) we need to flatter than the previous . 5) focal length and radius are related as f = -R/2      we know fnew,foldare 43 cms and 37.5cm using (1 - rnew/rold) =(1- fold/fnew )