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A coordinate system (in meters) is constructed on the surfaceof a pool table , a

ID: 1754215 • Letter: A

Question

A coordinate system (in meters) is constructed on the surfaceof a pool table , and three objects are placed on the coordinatesystem as follows: a 2 kg object at the origin, a 3.5 kg object at(0m,2m), and a 4.4 kg object at (3.9m,0m). At what angle does it act with respect to the positive x axis?Let counterclockwise be positive, within the limits of -180 degreesto 180 degress. Ans in units of degrees. A coordinate system (in meters) is constructed on the surfaceof a pool table , and three objects are placed on the coordinatesystem as follows: a 2 kg object at the origin, a 3.5 kg object at(0m,2m), and a 4.4 kg object at (3.9m,0m). At what angle does it act with respect to the positive x axis?Let counterclockwise be positive, within the limits of -180 degreesto 180 degress. Ans in units of degrees.

Explanation / Answer

          Giventhat the masse are m1 = 2kg ,m2 = 3.5 kg and m3 = 4.4kg           Thecoardinates are (x1,y1) = (0 , 0) , (x2,y2) = (0 , 2m) and(x3,y3) = (3.9m , 0) ------------------------------------------------------------------------------------------------          X-coardinate of the center of mass is Xcm = ( m1*x1 + m2*x2 +m3*x3) / ( m1 +m2 +m3 )                                                                            =( 0 + 0 + 4.4kg*3.9m) / ( 2kg + 3.5kg+ 4.4kg)                                                                            = 1.733 m           Y-coardinateof the center of mass is Ycm = ( m1*y1 + m2*y2 + m3*y3) / ( m1 +m2+m3 )                                                                            =( 0 + 3.5kg*2m + 0) / ( 2kg + 3.5kg+ 4.4kg)                                                                            =  0.70m           Theangle with positive x-axis is tan = Ycm / Xcm                                                                = tan-1 (Ycm / Xcm)                                                                   =tan-1 ( 0.70m / 1.733m )                                                                   =21.990                                                                                        =( 0 + 3.5kg*2m + 0) / ( 2kg + 3.5kg+ 4.4kg)                                                                            =  0.70m           Theangle with positive x-axis is tan = Ycm / Xcm                                                                = tan-1 (Ycm / Xcm)                                                                   =tan-1 ( 0.70m / 1.733m )                                                                   =21.990