A network of capacitors is connected across apotential difference V 0, as shown

Question

A network of capacitors is connected across apotential difference V0, as shown in Figure18.16.

Figure 18.16

(a)   What shouldV0 be so that the 60.0 µF capacitor will have18.0 µC of charge on each of its plates?

A network of capacitors is connected across apotential difference V0, as shown in Figure18.16. (a) What shouldV0 be so that the 60.0 F capacitor will have18.0 Mu C of charge on each of its plates? (b) Under the conditionsof part (a), how much total energy is stored in this network ofcapacitors?

Explanation / Answer

(a) What should V0 be so that the 60.0µF capacitor will have 18.0 µC of charge on each of its plates?       Charge on 60.0 uFcapacitor will equal charge on       the equivalent capacitor. Thus, we first determine       the equivalentcapacitor:       {Equivalent Capacitor} = C =           = 1/( 1/(30.0e-6) + 1/(20.0e-6 + 10.0e-6)+ 1/(60.0e-6) )           = 12.0e-6F      {Required VoltageV0} = V0 =           = Q/C    (

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---