A series circuit consists of a 0.048µF capacitor, a 0.100 µFcapacitor, and a 405

Question

A series circuit consists of a 0.048µF capacitor, a 0.100 µFcapacitor, and a 405 V battery. Findthe charge for the following situations. (a) on each of the capacitors
1 µC (0.048 µF capacitor)
2 µC (0.100 µF capacitor)
(b) on each of the capacitors if they are reconnected in parallelacross the battery
3 µC (0.048 µF capacitor)
4 µC (0.100 µF capacitor) (a) on each of the capacitors
1 µC (0.048 µF capacitor)
2 µC (0.100 µF capacitor)
(b) on each of the capacitors if they are reconnected in parallelacross the battery
3 µC (0.048 µF capacitor)
4 µC (0.100 µF capacitor)

Explanation / Answer

The equivalent capacitance is          Ceq =C1 C2 / ( C1+C2)                = 3.2432 x 10-8 F The Charge on each capacitor is same when connected inseries         Q = Ceq xV            =( 3.2432 x 10-8 )( 405V ) = 13.135 x10-6 C = 13.135C b) when connected in parallel         Q1=C1 V = (0.048F) x 405 = 19.44C         Q2 =C2 V =(0.1F) x 405 = 40.5C

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