I have two that I am completely stuck on. I need very detailed stepby step instr

Question

I have two that I am completely stuck on. I need very detailed stepby step instructions in how to solve these, otherwise I won't getit. Anyone who can help will be much appreciated.
1.) An automobile tire is pumped up to agauge pressure of 2.0 × 105 Pa when thetemperature is 27°C. What is its gauge pressure after the carhas been running on a hot day so that the tire temperature is77°C? Assume that the volume remains fixed and take atmosphericpressure to be 1.013 × 105 Pa.

1.6 ×105 Pa


2.6 ×105 Pa


3.6 ×105 Pa


5.9 ×105 Pa


7.9 ×105 Pa
2.) An ideal gas occupies 12liters at 293 K and 1 atm (76 cm Hg). Its temperature is now raisedto 373 K and its pressure increased to 215 cm Hg. The new volumeis:




0.2 liters


5.4 liters


13.6 liters


20.8 liters


none of these

If you only answer one of thequestions, could you please specify which one you are answering.Thank You.
1.) An automobile tire is pumped up to agauge pressure of 2.0 × 105 Pa when thetemperature is 27°C. What is its gauge pressure after the carhas been running on a hot day so that the tire temperature is77°C? Assume that the volume remains fixed and take atmosphericpressure to be 1.013 × 105 Pa.

1.6 ×105 Pa


2.6 ×105 Pa


3.6 ×105 Pa


5.9 ×105 Pa


7.9 ×105 Pa
2.) An ideal gas occupies 12liters at 293 K and 1 atm (76 cm Hg). Its temperature is now raisedto 373 K and its pressure increased to 215 cm Hg. The new volumeis:




0.2 liters


5.4 liters


13.6 liters


20.8 liters


none of these

If you only answer one of thequestions, could you please specify which one you are answering.Thank You.
1.6 ×105 Pa


2.6 ×105 Pa


3.6 ×105 Pa


5.9 ×105 Pa


7.9 ×105 Pa

Explanation / Answer

We know the Ideal gas equation is PV = nRT If the volume of the gas is fixed, then the pressure (P) ofthe gas is directly proportional to absolute temperature. Then (P2 / P1) = (T2 /T1)                P2 = (P1)(T2 /T1) .................. (1) Here P1 = 2.0 × 105 Pa         T1 =27°C             = 27 + 273 = 300 K         T2 =77°C            = 77 + 273 = 350K By substituting all these given values in the eq (1) we getthe value of the final pressure (P2) of the gas.         T1 =27°C             = 27 + 273 = 300 K         T2 =77°C            = 77 + 273 = 350K By substituting all these given values in the eq (1) we getthe value of the final pressure (P2) of the gas.

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