Help I can\'t get it Errr....... LifeSaver needed!!!! A block of unknown mass is

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Help I can't get it Errr....... LifeSaver needed!!!!
A block of unknown mass is attached to a spring with a springconstant of 6.50 N/m and undergoessimple harmonic motion with an amplitude of 10.0 cm. When the block is halfway between itsequilibrium position and the end point, its speed is measured to be29.0 cm/s. (a) Calculate the mass of the block.
1 kg
(b) Calculate the period of the motion.
2 s
(c) Calculate the maximum acceleration of the block.
3 m/s2 Help I can't get it Errr....... LifeSaver needed!!!!
A block of unknown mass is attached to a spring with a springconstant of 6.50 N/m and undergoessimple harmonic motion with an amplitude of 10.0 cm. When the block is halfway between itsequilibrium position and the end point, its speed is measured to be29.0 cm/s. (a) Calculate the mass of the block.
1 kg
(b) Calculate the period of the motion.
2 s
(c) Calculate the maximum acceleration of the block.
3 m/s2

Explanation / Answer

Spring constant k = 6.5 N / m Amplitude A = 10 cm = 0.1 m speed at half way v = 29 cm/ s                                = 0.29 m / s we know v = w [ A ^ 2 - x ^ 2 ] where displacement x = amplitude / 2                                    =A / 2 substitue this value in above we get  v = (3/ 2) * Aw from this angular speed w = 2v / A3                                        = 3.3486 rad / s So, mass of the block m = k / w ^ 2                                       =  0.579 kg     Period T = 2 / w               = 1.876 s    maximum accleration = Aw ^ 2                                   = 1.121 m / s^ 2     

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