Light of wavelength 625 nm shines through a single slit ofwidth 0.32 mm and form
ID: 1755080 • Letter: L
Question
Light of wavelength 625 nm shines through a single slit ofwidth 0.32 mm and forms a diffraction pattern on a flat screenlocated 8.0 m away. Determine the distance between the middle ofthe central bright fringe and the first dark fringe.a. 1.56 cm
b. 6.51 cm
c. 5.16 cm
d. 0.156 cm
e. 0.516 cm Light of wavelength 625 nm shines through a single slit ofwidth 0.32 mm and forms a diffraction pattern on a flat screenlocated 8.0 m away. Determine the distance between the middle ofthe central bright fringe and the first dark fringe. 1.56 cm 6.51 cm 5.16 cm 0.156 cm 0.516 cm
Explanation / Answer
Light of wavelength = 625 nm= 625 * 10 ^ -9 m single slit of width d = 0.32 mm = 0.32 * 10 ^ -3 m distance of the screen from slit D = 8.0m condition for 1 st dark fringe is d sin = at small angles sin ~ tan = y/ D So, d ( y / D ) = from this the distance between the middle of the centralbright fringe and the first dark fringe y = D / d = 1.5625* 10 ^ -2 m = 1.5625 cm