Please only give a walkthrough on howto complete this problem. I do not want the

Question

Please only give a walkthrough on howto complete this problem. I do not want the answer, just astep by step explanation of how to find the answer and why eachstep is necessary/what exactly it is doing. I will ratelifesaver for best explanation, NOT ANSWER. You give away theanswer, you won't get lifesaver.

A cylindrical air duct in an air conditioning system has a lengthof 5.5 m and a radius of 7.2 x 10^-2 m. A fan forces air ( n = 1.8x 10^-5 Pa·s) through the duct, such that the air in a room(volume = 280 m^3) is replenished every ten minutes. Determine thedifference in pressure between the ends of the air duct.
a. 14 Pa
b. 1.1 Pa
c. 0.023 Pa
d. 4.4 Pa
e. 0.47 Pa

Thanks again, andremember, I need a full explanation w/o an answer! Will ratelifesaver for explanation! Thanks again, andremember, I need a full explanation w/o an answer! Will ratelifesaver for explanation!

Explanation / Answer

the pressure of air through the room is P = n * t n = 1.8 * 10-5 Pa.s t = 10 minutes = 10 * 60 s = 600 s or P = 1.8 * 10-5 * 600 = 1080 * 10-5 Pa= 0.0108 Pa the pressure of air leaving the cylindrical air duct is P1 = * g * h = 0.001225 kg/m3 g = 9.8 m/s2 and h = 5.5 m or P1 = 0.001225 * 9.8 * 5.5 = 0.066 Pa the difference in pressure between the ends of the air ductis P = P1 - P = 0.066 - 0.0108 = 0.0552 Pa and h = 5.5 m or P1 = 0.001225 * 9.8 * 5.5 = 0.066 Pa the difference in pressure between the ends of the air ductis P = P1 - P = 0.066 - 0.0108 = 0.0552 Pa

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