1) A single slit forms a diffractionpattern, with the first minimum at an angle

Question

1) A single slit forms a diffractionpattern, with the first minimum at an angle of 40° fromcentral

maximum. Monochromatic light of450-nmwavelength is used. The same slit, illuminated bya

different monochromatic light source,produces a diffraction pattern with the second minimum ata

60° angle from the centralmaximum. The wavelength of this light, in nm, is closestto:

1)

2) Asingle slit, 2300 nm wide, forms a diffraction pattern whenilluminated by monochromatic light

of460-nmwavelength. The largest angle from the central maximum at which theintensity is zero

isclosest to:

2)

A)90° B) 81° C) 87° D) 78° E)84°

Explanation / Answer

2) The largest angle from the central maximum at whichthe intensity is zero is = 900 first minimum angle = 400 = 450*10-9m sin = m /a a = width of slit = m/sin where m = 1    a = 450*10-9/sin40 =700.9*10-9m for m = 2 angle = 600 = sina/m = 303*10-9m so A is correct answer. = sina/m = 303*10-9m so A is correct answer.

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