The electric dipole moment is 7.63 × 10 -29 C·m to the right. The external elect

Question

The electric dipole moment is 7.63 × 10-29C·m to the right. The external electric field is 9.87× 105 N/C parallel to the paper as shown. Find thetorque this external electric field exerts on the electricdipole.

The diagram has 2 forces,
Arrow 1 is pointing straight to the right, with a magnitude of7.63x10-29
Arrow 2 starts at beginning point of Arrow 1, but points down andto the left with a magnitude of 9.87x105
The angle between the 2 arrows is 111 degrees.

I used = _____° in finding the magnitude as follows:
torque = __ __ ______ =

Explanation / Answer

torque on an electric dipole in an electric field isjust .    = p x E =    p E sin = 7.63 x10-29 C-m * 9.87 x 105 N/C * sin 111 = 7.03 x10-23 N-m .       That is the magnitude. Thedirection can be found by using the right hand rule. . If p is "to the right"   and  E is "down and to the left", then the torqueis "into thepage"

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