(a) Given the local electric field of 169 N/C downward, whatis the acceleration

Question

(a) Given the local electric field of 169 N/C downward, whatis the acceleration experienced by an electron near the surface ofthe Earth? (b) What about a proton?
(c) Calculate the ratio of each acceleration to g =9.8 m/s2.       Electrona/g       Protona/g (a) Given the local electric field of 169 N/C downward, whatis the acceleration experienced by an electron near the surface ofthe Earth? (b) What about a proton?
(c) Calculate the ratio of each acceleration to g =9.8 m/s2.       Electrona/g       Protona/g

Explanation / Answer

( a). Accleration a = Eq / m where E = electric field = 169 N / C            q= charge = 1.6 * 10 ^ -19 C            m= mass = 9.11 * 10 ^ -31 kg plug the values   a = 29.68 * 10 ^ 12 m / s ^2 its acts along upward direction (b). Accleration a = Eq / m where E = electric field = 169 N / C            q= charge = 1.6 * 10 ^ -19 C            m= mass = 1.67 * 10 ^ -27 kg olug the values   a = 161.91 * 10^ 8 m / s ^ 2 (c). for electron a / g = 3.028*10^12 for proton   a / g = 16.522 * 10 ^ 8 its acts along upward direction where E = electric field = 169 N / C            q= charge = 1.6 * 10 ^ -19 C            m= mass = 1.67 * 10 ^ -27 kg olug the values   a = 161.91 * 10^ 8 m / s ^ 2 (c). for electron a / g = 3.028*10^12 for proton   a / g = 16.522 * 10 ^ 8 its acts along upward direction

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