Two equal charges Q separated by a distance D repel each otherwith a force of ma

Question

Two equal charges Q separated by a distance D repel each otherwith a force of magnitude 0.700 N. What is the magnitude ofthe force (in newtons) between two charges 6.00 Q separated by a distance of 7.00 D? Round off your answer tothree significant figures and include correct units (N fornewtons).
I have the answer but do not know how to get it??? Two equal charges Q separated by a distance D repel each otherwith a force of magnitude 0.700 N. What is the magnitude ofthe force (in newtons) between two charges 6.00 Q separated by a distance of 7.00 D? Round off your answer tothree significant figures and include correct units (N fornewtons).
I have the answer but do not know how to get it???

Explanation / Answer

The force between two charges is F = k * (Q * Q/D2) = k *(Q2/D2) or Q2 = (F * D2/k) or Q = (F/k)1/2 * D -----------(1) F = 0.700 N and k = (1/4o) = 9 *109 Nm2/C2 The force between two charges Q1 = Q2 =6.00Q is F1 = k * (Q1 *Q2/(7.00D)2) = k * (6.00Q *6.00Q/(7.00D)2) = (36/49) *(kQ2/D2) -----------(2) The value of Q is substituted from equation (1) in equation(2)

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