A fireman 44.0m away from a burning building directs a stream ofwater from a gro

Question

A fireman 44.0m away from a burning building directs a stream ofwater from a ground-level fire hose at an angle of 40 degrees abovethe horizontal. If the speed of the stream as it leaves thehose is 40.0 m/s, at what height will the stream of water strikethe building? ____ m (above ground level)
the work I did (but got it wrong) was: I found Vx= 30.64 m/s, Vy= 25.71 m/s, t= 1.44 s then I plugged my numbers into deltaY= Vy(t) + 1/2(g)(t)^2 =47.2m
help please! i will rate you lifesaver if webassign acceptsthe answer you help me find!
THANKS! ____ m (above ground level)
the work I did (but got it wrong) was: I found Vx= 30.64 m/s, Vy= 25.71 m/s, t= 1.44 s then I plugged my numbers into deltaY= Vy(t) + 1/2(g)(t)^2 =47.2m
help please! i will rate you lifesaver if webassign acceptsthe answer you help me find!
THANKS!

Explanation / Answer

        Given that theinitial velcotiy of water is U = 40 m/s         The angle ofprojection is = 400         The horizontaldistance is R = 44 m -------------------------------------------------------------------------------------        The maximum verticle height from theequation of motion is Vy2 - Uy2 =-2gH                                                                                                 0- Uy2 = -2gH           ( atmaximum height the veritcle final velcoity is Vy2 = 0)                                                                         H = Uy2 / 2g                                                                              =U2sin2 / 2g                                                                              =(40 m/s*sin400)2 /2*9.8m/s2                                                                              =---------- m        

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