Chapter 1 Problem 46P, out of the Cutnell and Johnson7th ED text for Physics The

Question

Chapter 1 Problem 46P, out of the Cutnell and Johnson7th ED text for Physics
The last step I cant figure out. I understand everything except thefollowing. I keep putting the inverse of cos 4.5 and my calc keepssaying error...... For xcos(theta)= 4.5 how did you get the anwser87. Chapter 1 Problem 46P, out of the Cutnell and Johnson7th ED text for Physics
The last step I cant figure out. I understand everything except thefollowing. I keep putting the inverse of cos 4.5 and my calc keepssaying error...... For xcos(theta)= 4.5 how did you get the anwser87.

Explanation / Answer

In this problem we have two equations xcos = 4.5-----(1) x sin = 18.2----(2) Divide (2) by (1)    tan = 18.2/4.5 = 4.044 = tan-1(4.044) = 760 From equation(2) x = 18.2/sin = 18.2/sin760 =18.7N From equation(2) x = 18.2/sin = 18.2/sin760 =18.7N

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