A body is moving along a square path ABCD with uniform speedof 5m/s Each side of

Question

A body is moving along a square path ABCD with uniform speedof 5m/s Each side of the square is 50m long. from the corner A findthe average velocity to each of teh four corners of thesquare.
Answer = <V AB> = 5 m/s along AB             = <V AC>= 3.5m / s along AC             =<V AD>= - 1.25 along AD A body is moving along a square path ABCD with uniform speedof 5m/s Each side of the square is 50m long. from the corner A findthe average velocity to each of teh four corners of thesquare.
Answer = <V AB> = 5 m/s along AB             = <V AC>= 3.5m / s along AC             =<V AD>= - 1.25 along AD

Explanation / Answer

The average velocity to each of the four corners of the squareare vAB = (a/t) t = (50/5) = 10 s or vAB = (50/10) = 5 m/s, vAC = (2a/t1) t = 2 * 10 = 20 s or vAC = (1.414 * 50/20) = 3.5 m/s vAD = (a/t2) t2 = 4 * 10 = 40 s or vAD = (50/40) = 1.25 m/s or vAD = -1.25 m/s This is because the body is moving along path DA and we getthe velocity along AD.The negative sign indicates that direction ofmotion of the body.

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