A block is sliding on a frictionlesshorizontal surface with an initial velocity

Question

      A block is sliding on a frictionlesshorizontal surface with an initial velocity of

15 m/s. The block then slidesdown a 5.0 m long frictionless down ramp that makes an angle of 37degrees with the horizontal. After the down ramp the blockresumes sliding on a frictionless horizontal surface at a constantvelocity.

     a. (5 points) What isthe final constant velocity of the block?

     b. (5 points) Howmuch time elapses from the time the block starts to speed up

         until itreaches its final velocity?

Please show ALLFormulas and work used to get your answer Thankyou

Explanation / Answer

the acceleration of the block down the rampis    g sin = 9.8 * sin37 =    5.898 m/s2 . The final velocity is found by: .     final velocity2 = initial velocity2 + 2ad = 152 +   2 * 5.898 * 5  = .          =    283.98 .      final velocity = 283.98 =    16.85 m/s . time = change in velocity / acceleration = (16.85 - 15) / 5.898   =    0.314seconds . The final velocity is found by: .     final velocity2 = initial velocity2 + 2ad = 152 +   2 * 5.898 * 5  = .          =    283.98 .      final velocity = 283.98 =    16.85 m/s . time = change in velocity / acceleration = (16.85 - 15) / 5.898   =    0.314seconds

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---