Girl and Sled A 42 kggirl and an 8.4 kg sled are on the frictionless ice of a fr

Question

Girl and Sled A 42 kggirl and an 8.4 kg sled are on the frictionless ice of a frozenlake, 12 m apart but connected by arope of negligible mass. The girl exerts a horizontal 5.9 N force on the rope. (a) What is the acceleration of the sled?
m/s2
(b) What is the acceleration of the girl?
                        m/s2
(c) How far from the girl's initial position do they meet?
m (a) What is the acceleration of the sled?
m/s2
(b) What is the acceleration of the girl?
                        m/s2
(c) How far from the girl's initial position do they meet?
m

Explanation / Answer

   mass of the girl, m 1 = 42kg    mass of the sled, m 2 = 8.4kg    distance between girl and sled, d = 12 m     force exerted by the girl , F = 5.9 N    According to Newton's third law both girland sled experience same force (a)   Acceleration of the sled, a 2=F / m 2 = 5.9 / 8.4 = 0.7 m/s^2 (b)    Acceleration of the girl, a1 = F / m1 = 5.9 / 42 = 0.14 m/s^2 (c)     Let they meet at a distance of xfrom the girl          According tolaw of conservation of momentum           m1 (x) = m 2 ( d - x )            42 x = 8.4 ( 12 - x )             42 x = 100.8 - 8.4 x                50.4x = 100.8                   x= 2 m ( from girl)

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