Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A small conducting spherical shellwith inner radius a and outerradius b is conce

ID: 1761496 • Letter: A

Question


A small conducting spherical shellwith inner radius a and outerradius b is concentric with a larger conductingspherical shell with inner radius c and outerradius d. The inner shell has a total charge-2qand the outer shell has a total charge+3q. A small conducting spherical shellwith inner radius a and outerradius b is concentric with a larger conductingspherical shell with inner radius c and outerradius d. The inner shell has a total charge-2qand the outer shell has a total charge+3q.

Which of the following statements aretrue: A) The radial component of theelectric field in the region r greater than d is given by+1q/(40 r2).
B) The total charge on the outer surface of the small shell is-2q.
C) The radial component of the electric field in the region c lessthan r less than d is given by-2q/(40 r2).
D) The total charge on the outer surface of the large shell is+1q.
E) The total charge on the inner surface of the large shell iszero.
F) The electric field in the region r less than a is zero.
G) The total charge on the inner surface of the small shell is-5q. Which of the following statements aretrue: A) The radial component of theelectric field in the region r greater than d is given by+1q/(40 r2).
B) The total charge on the outer surface of the small shell is-2q.
C) The radial component of the electric field in the region c lessthan r less than d is given by-2q/(40 r2).
D) The total charge on the outer surface of the large shell is+1q.
E) The total charge on the inner surface of the large shell iszero.
F) The electric field in the region r less than a is zero.
G) The total charge on the inner surface of the small shell is-5q.

Explanation / Answer

1. true 2. Qinner,inside/4*a = [Qinner,inside +Qinner,outside]/4*b for static condition in innershell.     So, Q1/a = [Q1+Q2]/b     where Q1+Q2 = -2q      => Q1*b = 2Q1*a + 2q*a      => Q1 = 2qa/(b-2a)      => Q2 = -2qb/(b-2a)      So, the charge is Q2 =-2qb/(b-2a).    Hence, the answer is false.