1) What is the direction of the accelerationof the object at moment 5? 2) What i

Question

1) What is the direction of the accelerationof the object at moment 5?

2) What is the direction of the accelerationof the object at moments 0 and 10? Enter the letters corresponding tothe arrows with these directions from the compass rose in thefigure, separated by commas. Type Z if the accelerationvector has zero length. directions at time step 0, time step 10 = 2) What is the direction of the accelerationof the object at moments 0 and 10? Enter the letters corresponding tothe arrows with these directions from the compass rose in thefigure, separated by commas. Type Z if the accelerationvector has zero length. directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = directions at time step 0, time step 10 = Enter the letter of the arrow withthis direction from the compass rose in the figure. TypeZ if the acceleration vector has zero length.

Explanation / Answer

1)The direction of the acceleration of the object at moment 5is towards the right.This is because the pendulum is oscillatingfrom the left to the right direction. 2)The forces acting on the pendulum when it is makingoscillations from left to right are: Fx = mg * sin or m * ax = mg * sin or ax = g * sin ---------(1) and Fy = T + (-mg * cos) = 0 or T = mg * cos ----------(2) The direction of acceleration of the object at moments 0 and10 is towards right.This is because the motion of the pendulum isin the right direction.The value of acceleration is given byequation (1).The acceleration value decreases as the objectadvances in the right direction.This is because the value ofsin decreases as the object approaches the equilibriumposition. Again the value of acceleration increases as the object movesfrom the equilibrium position towards the left direction.

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