a) A photon ofwavelength 486.1 nm is emitted. What transition of the electronpro

Question

a) A photon ofwavelength 486.1 nm is emitted. What transition of the electronproduced the photon?
b) A photon of energy 10.2 eV interacts with the atom. If thephoton is absorbed, what energy level transition must haveoccured?
c) The electron undergoes a transition from energy level 5 toenergy 2. Is a photon emitted or absorbed? What is the energy ofthis photon?
d) If the electron is in the ground state (energy level 1), whathappens when a photon of energy 15.0 eV is absorbed by theatom?


thank you much in advance for any help! :D a) A photon ofwavelength 486.1 nm is emitted. What transition of the electronproduced the photon?
b) A photon of energy 10.2 eV interacts with the atom. If thephoton is absorbed, what energy level transition must haveoccured?
c) The electron undergoes a transition from energy level 5 toenergy 2. Is a photon emitted or absorbed? What is the energy ofthis photon?
d) If the electron is in the ground state (energy level 1), whathappens when a photon of energy 15.0 eV is absorbed by theatom?


thank you much in advance for any help! :D

Explanation / Answer

PART A>>>    The electronic transitionis from an initial upper level of n = 4 to a lower final level of m= 2. This is the visible Balmer series. This can be verified by using the Bohr eqn :   c / = [ Z2 m e4 / (8o2 h3 ) ] [ 1 /m2 - 1 / n2 ] solving for and using the Rydberg constant, we getsimplified form: = [ 1 / 1.097E7 ] [ n2m2 / (n2 - m2 ) ] plugging in value for n and m, weget:      = [ 1 / 1.097E7] [42   22 / (42 -22 )] = 486.2 nm PART B>>>    A difference in twoenergy levels of 10.2 eV means that the initial lower level was m=1and the final upper level was n=2. This is the Lymanseries. The best way to verify this is to use   E = 1240 / where E is eV and is nm to calculate wavength = 121.6 nm and then use the eqn in part a. PART C>>> from 5 to 2, energy in form of aphoton is emitted.   First, calculate using eqn in part a, and thenfind E from eqn in part b.     PART D>>>   There are NO two energy levelsin H that have a difference of exactly 15 eV.   Thus,nothing happens. ie, the photon with energy fo 15 eV is NOT absorbed atall.

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