A 50.4 g block of copper whosetemperature is 400 K is placed in aninsulating box

Question

A 50.4 g block of copper whosetemperature is 400 K is placed in aninsulating box with a 160 g block oflead whose temperature is 200 K. (Usethe data of Table 18-3.) (a) What is the equilibrium temperature of thetwo-block system?
1 K
(b) What is the change in the internal energy of the system betweenthe initial state and the equilibrium state?
2 J
(c) What is the change in the entropy of the system? (a) What is the equilibrium temperature of thetwo-block system?
1 K
(b) What is the change in the internal energy of the system betweenthe initial state and the equilibrium state?
2 J
(c) What is the change in the entropy of the system?

Explanation / Answer

mass of copper M = 50.4 g initial temp of copper t = 400 K Mass of lead m = 160 g initial temp of lead t ' = 200 K Specific heat of copper C = 0.386 J / g K Specific heat of lead c = 0.128 J / g K heat lost by copper = heat gain by lead            MC (400-T ) = mc ( T -200)         19.4544( 400-T ) =20.48 ( T -200)            400-T = 1.0527 ( T -200)                      = 1.0527 T - 210.54        2.0527 T =610.54                    T = 297.43 K Equilibrium temperature T = 297.43 K Change in entropy of the system = 0 Since it is insulating i.e., the process is adiabatic

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