A constant force is applied to an object, causing the object toaccelerate at 6 m

Question

A constant force is applied to an object, causing the object toaccelerate at 6 m/s2. Whatwould the acceleration be if each of the following things happened(from the initial state)? (a) the force is doubled
1 m/s2
(b) the object's mass is doubled
2 m/s2
(c) the force and the object's mass are both doubled
3 m/s2
(d) the force is doubled and the object's mass is halved
4 m/s2 (a) the force is doubled
1 m/s2
(b) the object's mass is doubled
2 m/s2
(c) the force and the object's mass are both doubled
3 m/s2
(d) the force is doubled and the object's mass is halved
4 m/s2

Explanation / Answer

Accleration a = 6 m / s ^ 2 (a). force is doubled then accleration is doubled So, accleration a = 12 m / s ^ 2   Since from newton law f = ma (b).mass is doubled then accleration id half i.e., accleration a= 3 m / s ^2 Since f = ma (c). Accleration is not changed . i.e., accleration a = 6 m / s ^ 2 (d). accleration = 4 ( 6 ) =24 m / s ^ 2

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