A woman is riding a jetski at a speed of 28 m/s and notices aseawall straight ah
ID: 1762854 • Letter: A
Question
A woman is riding a jetski at a speed of 28 m/s and notices aseawall straight ahead. The farthest she can lean the craft inorder to make a turn is 19°. This situation is like that of acar on a curve that is banked at an angle of 19°. If she triesto make the turn without slowing down, what is the minimum distancefrom the seawall that she can begin making her turn?A woman is riding a jetski at a speed of 28 m/s and notices aseawall straight ahead. The farthest she can lean the craft inorder to make a turn is 19°. This situation is like that of acar on a curve that is banked at an angle of 19°. If she triesto make the turn without slowing down, what is the minimum distancefrom the seawall that she can begin making her turn?
Explanation / Answer
Applying Newton's second law along the radius and first lawin the vertical direction is Nsin = mv2 / r and N cos = mg r = v2/ g*tan = 28*28 / 9.8*tan19 = 232.55 m the minimum distance from the seawall that she can begin making herturn is 232.55 m.