A 4.00-kg box is sliding across thehorizontal floor of an elevator. The coeffici

Question

A 4.00-kg box is sliding across thehorizontal floor of an elevator. The coefficient of kineticfriction between the box and the floor is 0.390. Determine the kinetic frictional force thatacts on the box for each of the following cases. (a) The elevator is stationary.
1(No Response) N

(b) The elevator is accelerating upward with an acceleration whosemagnitude is 2.80 m/s2.
2(No Response) N

(c) The elevator is accelerating downward with an accelerationwhose magnitude is 2.80m/s2.
3 (a) The elevator is stationary.
1(No Response) N

(b) The elevator is accelerating upward with an acceleration whosemagnitude is 2.80 m/s2.
2(No Response) N

(c) The elevator is accelerating downward with an accelerationwhose magnitude is 2.80m/s2.
3

Explanation / Answer

mass m = 4 kg The coefficient of kinetic friction between the box and thefloor = 0.390 (a) . kinetic frictional force = mg                                         = 0.39 * 4 * 9.8 = 15.288 N (b). Kinetic frictional force = m ( a+ g )                                        = 0.39 * 4 * ( 2.8 +9.8 )                                        = 19.656 N (c).kinetic frcitinal force = m ( g - a )                                    = 0.39 * 4 ( 9.8 -2.8 )                                   = 10.92 N (a) . kinetic frictional force = mg                                         = 0.39 * 4 * 9.8 = 15.288 N (b). Kinetic frictional force = m ( a+ g )                                        = 0.39 * 4 * ( 2.8 +9.8 )                                        = 19.656 N (c).kinetic frcitinal force = m ( g - a )                                    = 0.39 * 4 ( 9.8 -2.8 )                                   = 10.92 N

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