Working Like a Horse. Your job is to lift25-kg crates a vertical distance of0.70

Question

Working Like a Horse. Your job is to lift25-kg crates a vertical distance of0.70 m from the ground onto the bed ofa truck. (a) How many crates would you have to load ontothe truck in one minute for the average power output you use tolift the crates to equal 0.50 hp?
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(b) How many crates would you have to load onto the truck in oneminute for an average power output of 150 W?
2 (a) How many crates would you have to load ontothe truck in one minute for the average power output you use tolift the crates to equal 0.50 hp?
1

(b) How many crates would you have to load onto the truck in oneminute for an average power output of 150 W?
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Explanation / Answer

massm = 25 kg vertical height h = 0.7 m work done to load one crate W = mgh                                                  = 25 * 9.8 * 0.7 = 171.5 J Power P = 0.5 hp              = 0.5 * 746 Watt time t = 1 min = 60 s So, energy E = Pt                     = 22380 J So, No.of ctares N = E / W                               = 130.49 ~ 130 (b). power P ' = 150 watt time t= 1min = 60s energy E ' = P ' t So, No.of crates N ' = E ' / W                                = 52.47 ~ 52            

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