Chopping Block Two horizontal forces act on a1.8 kg chopping block that can slid

Question

Chopping Block Two horizontal forces act on a1.8 kg chopping block that can slideover a frictionless kitchen counter, which lies in an xyplane. One force is FA = (3.0 N) i + (4.3 N) j. Find the accelerationof the chopping block in unit-vector notation when the other forceFB is as given in each part below. (a) FB =(-3 N) i +(-4.3 N) j
1???m/s2i + 2???? m/s2j

(b) FB = (-3 N) i + (4.3 N) j
3??? m/s2i + 4???? m/s2j

(c) FB = (3.0 N) i + (-4.3 N) j
5??? m/s2i + 6???m/s2j (a) FB =(-3 N) i +(-4.3 N) j
1???m/s2i + 2???? m/s2j

(b) FB = (-3 N) i + (4.3 N) j
3??? m/s2i + 4???? m/s2j

(c) FB = (3.0 N) i + (-4.3 N) j
5??? m/s2i + 6???m/s2j

Explanation / Answer

mass m = 1.8 kg FA = 3 i + 4.3 j (a). FB = -3 i -4.3 j net force F = FA + FB = 0 i + 0 j So, accleration a = F / m = 0 i + 0 j (b). FB = -3 i + 4.3 j Net force F = FA+FB                    =0 i + 8.6 j So, accleration a = F / m                         = 0 i + 4.777 j (c).FB = 3 i -4.3 j So, F = 6 i + 0 j So, accleration a = F / m                          = 3.333 i + 0 j

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---