A)Two masses m1 and m, with m1>m2, have equal kinetic energy.How do the magnitud

Question

A)Two masses m1 and m, with m1>m2, have equal kinetic energy.How do the magnitudes of their momenta compare?
1 a. p1 < p2
b. p1 =p2    
c. p1 > p2


B)Question When a person is involved in a car accident, why is thelikelihood of injury greater in a head-on collision as opposed tobeing hit from behind? Answer using the concepts of relativevelocity, momentum, and average force. (Select all thatapply.)
1 The momentum of the driver relative to theground is greater in a head-on collision.
The change in momentum is greater in thehead-on collision.
The average force on the driver is greaterin the head-on collision.
The collapse of the crumple zone in thefront of the car occurs only in the head-on collision.
The velocity of the driver relative to theground is greater in a head-on collision.
1 1 The momentum of the driver relative to theground is greater in a head-on collision.
The change in momentum is greater in thehead-on collision.
The average force on the driver is greaterin the head-on collision.
The collapse of the crumple zone in thefront of the car occurs only in the head-on collision.
The velocity of the driver relative to theground is greater in a head-on collision. 1 The momentum of the driver relative to theground is greater in a head-on collision.
The change in momentum is greater in thehead-on collision.
The average force on the driver is greaterin the head-on collision.
The collapse of the crumple zone in thefront of the car occurs only in the head-on collision.
The velocity of the driver relative to theground is greater in a head-on collision. 1

Explanation / Answer

we know kineticx energy K = P ^ 2 / 2m Kinetic energy K = constant . So, P ^ 2 m       P m ( P ' / P ) = [ m ' / m ] given m > m '   So, P ' / P < 1              i.e. P 2 < P 1 (b). The change inmomentum is greater in the head-on collision.

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